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4a^2+12=12
We move all terms to the left:
4a^2+12-(12)=0
We add all the numbers together, and all the variables
4a^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{8}=0$
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